µÚһƪ¹¤³ÌÈÈÁ¦Ñ§ ×ÔÈ»½çµÄÄÜÔ´ÖÐÈÈÄܵÄÀûÓÃ×îΪÆÕ±é¡£ÈÈÄÜÊÇָú¡¢Ê¯ÓÍ¡¢ÌìÈ»ÆøµÈȼÁÏȼÉÕ²úÉúµÄÈÈËù¾ßÓеÄÄÜÁ¿¡£¾Ýͳ¼Æ£¬Ä¿Ç°ÎÒ¹úÀûÓõÄÄÜÔ´ÖÐÈÈÄÜÕ¼ÁË90%ÒÔÉÏ¡£ÊÀ½çÉÏÆäËû¹ú¼ÒҲƽ¾ù³¬¹ýÁË85%£¬¿É¼ûÈÈÄܵÄÀûÓöàôÆÕ±é¡£ ÈÈÄÜ×îÖ±½ÓµÄÓ¦ÓÃÊǼÓÈÈ£¬ÀûÓÃȼÁÏȼÉÕ²úÉúµÄÈÈÀ´×ö·¹¡¢È¡Å¯¡¢ºæ¸É¡¢ÉÕÖÆÌÕ´ÉשÍß¡¢Ò±Á¶µÈ¡£ÕâÊÇÈÈÄÜÀûÓõijõ¼¶½×¶Î£¬Ò²ÊÇÔçÆÚÈÈÄÜÀûÓõÄΨһ;¾¶¡£ÈÈÄܵÄÖ±½ÓÀûÓÃĿǰҲÒÀÈ»´æÔÚ¡£ ÈÈÄܵļä½ÓÀûÓÃÊÇÌṩ¶¯Á¦¡£ÕôÆû»úµÄ³öÏÖ¿ª´´ÁËÈÈÄÜÀûÓõÄмÍÔª£º ͨ¹ýÕôÆû»ú½«ÈÈÄÜת»»Îª»úеÄÜÒÔÍÆ¶¯»úÆ÷¡¢Æû³µ¡¢»ð³µ¡¢ÂÖ´¬¡£ÈÈÄÜת»»ÌṩµÄ¶¯Á¦´úÌæÁËÈËÁ¦¡¢ÐóÁ¦£¬¼«´óµØ´Ù½øÁËÉú²úÁ¦µÄ·¢Õ¹¡£ÈËÀà´Ó´Ë½øÈëÁ˹¤Òµ»¯Ê±´ú¡£¶ÔÓÚ¹¤ÒµÉú²ú£¬ÈÈÄܵ͝Á¦ÀûÓÃÊÇÒ»ÖÖ¼ÛÖµ¸ü¸ß¡¢Ç°¾°¸üΪ¹ãÀ«µÄÀûÓÃ;¾¶¡£ÕâÊÇÈÈÄÜÀûÓõĸ߼¶½×¶Î¡£ ÈÈÄÜת»»²úÉúµÄ»úеÄÜÍ϶¯·¢µç»úÓֿɲúÉúµçÄÜ£¬µçÄܵÄÉú²úÖ÷Òª½èÖúÓÚÈÈÄܵ͝Á¦ÀûÓᣠÈËÀàÉç»á·¢Õ¹µÄÀúÊ·ÓëÈÈÄܵÄÀûÓÃϢϢÏà¹Ø¡£Ä¿Ç°£¬ÊµÏÖÈÈÄÜÓë»úеÄÜת»»µÄÈÈ»ú£¬ÒÑ´ÓÕôÆû»ú·¢Õ¹µ½ÕôÆûÂÖ»ú¡¢ÄÚȼ»ú¡¢È¼ÆøÂÖ»úÒÔ¼°ÅçÆø·¢¶¯»úµÈ£¬ÈÈÄÜת»»µÄЧÂʵõ½ÌáÉý£¬ÈÈÄܶ¯Á¦ÀûÓõļÛÖµÒ²¾Í¸ü´ó¡£ ÖÆÀä×°Öã¬Èç¿Õµ÷¡¢±ùÏ䣬Æä¹¤×÷¹ý³ÌÓëÈÈ»úÏà·´¡£×î³£¼ûµÄÕôÆøÑ¹ËõÖÆÀä×°ÖÃÒÔÏûºÄ»úеÄÜΪ´ú¼Û£¬½«ÈÈÁ¿´ÓµÍÎÂÈÈÔ´×ªÒÆµ½¸ßÎÂÈÈÔ´£¬ÒÔʵÏÖÈ˹¤ÖÆÀä¡£ÖÆÀä¹ý³ÌÉæ¼°»úеÄÜÏòÈÈÄܵÄת»»¡£ ÈÈÄܶ¯Á¦ÀûÓõĺËÐÄÊÇÄÜÁ¿ÐÎʽµÄת±ä¡£Òò´Ë£¬ÄÜÁ¿×ª»»µÄ¹æÂÉÊܵ½ÆÕ±éµÄ¹Ø×¢¡£ÈÈÁ¦Ñ§´Ó¶øµÃµ½¿ìËÙ·¢Õ¹¡£ÈÈÄܵ͝Á¦ÀûÓÃÓëÈÈÁ¦Ñ§Êµ¼ÊÉÏÊÇÏ໥´Ù½ø£¬¹²Í¬·¢Õ¹µÄ¡£ÁíÒ»¸öÊܵ½¹Ø×¢µÄÎÊÌâÊÇÈÈ»úµÄЧÂÊ¡£ÎÞÂÛºÎÖÖÈÈ»ú£¬ÔÚʵÏÖÈÈÄÜÓë»úеÄܵÄת±ä¹ý³ÌÖÐ×ÜÓнϴó·Ý¶îµÄÄÜÁ¿²»ÄÜÀûÓöø±»Ëðʧµô£¬ÈÈ»úµÄÈÈЧÂÊÒ²¾Í²»¸ß¡£ÔçÆÚÕôÆû»úµÄÈÈЧÂÊÖ»ÓÐ1%~2%£¬ÏÖ´úÈ¼ÆøÂÖ»úµÄÈÈЧÂÊÒ²²»¹ý40%×óÓÒ¡£ ΪÁËÓÐЧµØÊµÏÖÈÈÄÜÓë»úеÄܵÄת»»£¬Ìá¸ßÈÈ»úµÄÈÈЧÂÊ£¬¾Í±ØÐëÊìϤ¡¢ÕÆÎÕºÍÑо¿ÄÜÁ¿×ª»»µÄ¹æÂÉ¡£ ÈÈÁ¦Ñ§ÊÇÑо¿ÓëÈÈÏÖÏóÓйصÄÄÜÁ¿×ª»»¹æÂɵÄÒ»ÃÅ¿ÆÑ§£¬¹¤³ÌÈÈÁ¦Ñ§ÊÇ´Ó¹¤³ÌµÄ½Ç¶È³ö·¢£¬·ÖÎöºÍÑо¿ÈÈÄÜÓë»úеÄÜÖ®¼äÏ໥ת»»µÄѧ¿Æ¡£ ¹¤³ÌÈÈÁ¦Ñ§µÄÖ÷ÒªÄÚÈݰüÀ¨»ù±¾¸ÅÄî¡¢»ù±¾¶¨ÂÉ£¬Èçϵͳ¡¢²ÎÊý£¬ÈÈÁ¦Ñ§µÚÒ»¶¨ÂÉÓëµÚ¶þ¶¨ÂÉ¡£ÕâЩÄÚÈÝÊǹ¤³ÌÈÈÁ¦Ñ§µÄÀíÂÛ»ù´¡¡£¶øÈÈÄÜÓë»úеÄܵÄת»»ÊÇͨ¹ý¹¤×÷½éÖÊÔÚÈÈ»ú»òÖÆÀä×°ÖÃÖеÄ״̬±ä»¯¹ý³Ì£¬ÒÔ¼°ÓÉÈô¸É¹ý³Ì×é³ÉµÄÑ­»·À´ÊµÏֵġ£Òò´Ë£¬¹¤×÷½éÖʵÄÐÔÖÊ¡¢×´Ì¬±ä»¯¹ý³ÌºÍÑ­»·µÄ·ÖÎöÓëÈÈÁ¦¼ÆËãÒ²Êǹ¤³ÌÈÈÁ¦Ñ§Ñо¿µÄÖØÒªÄÚÈÝ¡£ ¹¤³ÌÈÈÁ¦Ñ§²ÉÓúê¹ÛÑо¿·½·¨£¬²»Éæ¼°¹¤ÖʵÄ΢¹Û½á¹¹ºÍ΢¹ÛÐÐΪ¡£¹¤³ÌÈÈÁ¦Ñ§Ò²¾­³£²ÉÓóéÏ󡢸ÅÀ¨¡¢ÀíÏ뻯ºÍ¼ò»¯µÄ·½·¨¡£±ÈÈ罫¿ÕÆø¡¢¹øÂ¯ÑÌÆø¡¢ÄÚȼ»úÈ¼ÆøÊÓΪÀíÏëÆøÌ壬¼ò»¯Á˼ÆËãÓÖά³ÖÁ˹¤³Ì¼ÆËãµÄ¾«¶È¡£¼ò»¯Óë³éÏóµÄʵÖÊÊÇÍ»³öÖ÷Ҫì¶Ü£¬ºöÂÔ´ÎÒªÒòËØ£¬´Ó¶ø¸üÈ«Ãæ¡¢¸üÉî¿ÌµØ·´Ó³¿Í¹Û¹æÂÉ¡£Ñ§Ï°ÈÈÁ¦Ñ§ÒªÄÜÊÊÓ¦ÕâÖÖ·½·¨¡£ µÚ1ÕÂÈÈÁ¦Ñ§»ù±¾¸ÅÄî 1.1¹¤ÖÊÓëÈÈÔ´ µçÄÜÉú²ú¹ý³ÌÖÐÈÈÄÜÊ×ÏÈת»»Îª»úеÄÜ£¬ÔÙת»»ÎªµçÄÜ¡£ÈÈÄÜÓë»úеÄܵÄת»»ÒÔË®ÕôÆøÎªÃ½½é¡£Ë®ÕôÆøÊÇÈÈÄܵÄÔØÌ壬ˮÕôÆøÔÚÆûÂÖ»úÖÐÅòÕÍ×ö¹¦£¬Çý¶¯ÆûÂÖ»ú£¬ÊµÏÖÁËÈÈÄÜÓë»úеÄܵÄת»»¡£ÖÆÀä×°ÖõÄÄÜÁ¿×ª»»Ò²Òª½èÖú°±¡¢·úÀû°ºµÈÖÆÀä¼Á¡£ÈÈÄÜÓë»úеÄÜÏ໥ת»»Ëù½èÖúµÄý½éÎïÖʳÆÎª¹¤ÖÊ¡£¹¤ÖʱØÐë¾ßÓÐÁ¼ºÃµÄÁ÷¶¯ÐÔºÍÓëÆä¹¤×÷ÏàÊÊÓ¦µÄÈÈÁ¦ÐÔÄÜ¡£ ¾ßÓÐÎÞÏÞ´óÈÈÈÝÁ¿µÄϵͳÔÚÈÈÁ¦Ñ§ÖгÆÎªÈÈÔ´¡£ÎÞÏÞ´óÈÈÈÝÁ¿ÊÇÖ¸Ôڷųö»òÎüÊÕÓÐÏÞÈÈÁ¿Ê±¹¤ÖÊζÈûÓÐÃ÷ÏԵı仯¡£¸ù¾Ýζȵĸߵͣ¬ÈÈÔ´ÓÖ¿É·ÖΪ¸ßÎÂÈÈÔ´ºÍµÍÎÂÈÈÔ´¡£ÏÄÌìÊÒÄÚζȽÏÊÒÍâζȵͣ¬ÊÒÄÚ³ÆÎªµÍÎÂÈÈÔ´£¬ÊÒÍâ³ÆÎª¸ßÎÂÈÈÔ´£» ¶¬ÌìÔò¸ÕºÃÏà·´¡£ 1.2ÈÈÁ¦ÏµÍ³ ͼ1-1ÈÈÁ¦ÏµÍ³ (a) ±Õ¿Úϵͳ£» (b) ¿ª¿Úϵͳ ¸ù¾ÝÑо¿¹¤×÷µÄÐèÒª£¬Ñ¡È¡Ä³Ò»·¶Î§ÄڵŤÖÊ×÷ΪÑо¿¶ÔÏó£¬ÒÔÑо¿ÆäÈÈÁ¦Ñ§¹æÂÉ£¬ÕâÖÖÑо¿¶ÔÏó³ÆÎªÈÈÁ¦ÏµÍ³£¬¼ò³ÆÏµÍ³£¬Èçͼ1-1Ëùʾ¡£ÏµÍ³ÊÇΪÁËÑо¿µÄÐèÒª¶øÈËΪ¶¨ÒåµÄ¡£ÏµÍ³Ö®ÍâµÄÎïÌåͳ³ÆÎªÍâ½ç»ò»·¾³¡£ÏµÍ³ÓëÍâ½çµÄ·Ö½çÃæ³ÆÎª±ß½ç»ò½çÃæ¡£ÏµÍ³ÓëÍâ½çÖ®¼äµÄ·Ö½çÃæ¿ÉÒÔÊÇÕæÊµµÄ£¬Ò²¿ÉÒÔÊǼÙÏëµÄ¡£Í¼1-1(a)ÖÐÈ¡ÆøÌ幤ÖÊΪϵͳʱ£¬Æû¸×ÄڱںͻîÈûÄÚ±ÚÊÇÕæÊµ´æÔڵĽçÃæ£» ͼ1-1(b)Öнø¿Ú½ØÃæÓë³ö¿Ú½ØÃæ±ãÊǼÙÏëµÄ½çÃæ¡£½çÃæ¿ÉÒÔÊǹ̶¨²»±äµÄ£¬Ò²¿ÉÒÔÊDZ䶯µÄ£¬Í¼1-1(a)Öе±»îÈûÒÆ¶¯Ê±·¢Éú±ä»¯µÄ½çÃæÊDZ䶯µÄ¡£ Ò»°ãÀ´Ëµ£¬ÏµÍ³ÓëÍâ½ç×ÜÊÇ´¦ÓÚÏ໥×÷ÓÃÖ®ÖУ¬±Ë´ËÖ®¼ä¿ÉÄܽøÐÐÄÜÁ¿ºÍÖÊÁ¿½»»»£¬°´ÏµÍ³ÓëÍâ½ç½øÐÐÄÜÁ¿ºÍÖÊÁ¿½»»»µÄÇé¿ö¿É½«ÏµÍ³·ÖΪÒÔϼ¸ÖÖ¡£ (1) ±Õ¿ÚϵͳϵͳÓëÍâ½çÎÞÎïÖʽ»»»£¬»òÕß˵ûÓÐÎïÖÊ´©¹ý±ß½ç£¬ÏµÍ³ÄÚµÄÎïÖÊ×ÜÁ¿±£³Öºã¶¨²»±ä¡£Í¼1-1(a)Ëùʾ¾ÍÊDZտÚϵͳ¡£ (2) ¿ª¿ÚϵͳϵͳÓëÍâ½çÓÐÎïÖʽ»»»£¬»òÕß˵ÓÐÎïÖÊ´©¹ý±ß½ç£¬ÏµÍ³ÄÚµÄÎïÖÊ×ÜÁ¿¿ÉÒÔ±£³Öºã¶¨»ò·¢Éú±ä»¯¡£Í¼1-1(b)ËùʾΪ¿ª¿Úϵͳ£¬ÔËÐÐÖй¤Öʲ»¶ÏµØÁ÷½øÁ÷³ö¡£ (3) ¾øÈÈϵͳϵͳÓëÍâ½çÎÞÈÈÁ¿½»»»£¬µ«¿ÉÒÔÓй¦Á¿ºÍÖÊÁ¿µÈ½»»»¡£ (4) ¹ÂÁ¢ÏµÍ³ÏµÍ³ÓëÍâ½ç¼ÈÎÞÄÜÁ¿(°üÀ¨¹¦Á¿ºÍÈÈÁ¿)½»»»ÓÖÎÞÖÊÁ¿½»»»¡£ ×ÔÈ»½çÖеÄÎïÖʶ¼ÊÇÏ໥ÁªÏµ¡¢Ïà»¥ÖÆÔ¼ºÍÏ໥×÷Óõ쬾ø¶ÔµÄ¾øÈÈϵͳºÍ¹ÂÁ¢ÏµÍ³²¢²»´æÔÚ¡£µ«ÈôϵͳÓëÍâ½çµÄÈÈÁ¿¡¢¹¦Á¿¡¢ÖÊÁ¿µÄ½»»»ÉõС£¬ÆäÓ°Ïì¿ÉºöÂÔ²»¼Æ£¬¾Í¿ÉÒÔ½«ÕâÑùµÄϵͳÊÓΪ¾øÈÈϵͳ»ò¹ÂÁ¢ÏµÍ³¡£ 1.3ÈÈÁ¦×´Ì¬Óë״̬²ÎÊý 1.3.1¹¤ÖÊÈÈÁ¦×´Ì¬ ÈÈÁ¦×´Ì¬ÊÇָijһ˲¼äϵͳ¹¤ÖÊËù³ÊÏֵĺê¹ÛÎïÀí×´¿ö£¬ÈÈÁ¦×´Ì¬ÓÖ¼ò³ÆÎª×´Ì¬¡£×´Ì¬Í¨¹ýÎïÀíÁ¿µÄÃèÊö¶ø±äµÃÐÎÏó¡¢¾ßÌå¡£ÓÃÒÔÃèÊö¹¤ÖÊ״̬µÄºê¹ÛÎïÀíÁ¿³ÆÎª×´Ì¬²ÎÊý¡£Ö÷ÒªµÄ״̬²ÎÊýÊÇζȡ¢Ñ¹Á¦ºÍ±ÈÌå»ý¡£ ×îÖµµÃ¹Ø×¢µÄ״̬ÊÇÆ½ºâ״̬¡£Ëùνƽºâ״̬ÊÇÖ¸ÔÚûÓÐÍâ½ç×÷ÓÃ(ÖØÁ¦³¡³ýÍâ)µÄÌõ¼þÏ£¬ÏµÍ³µÄ״̬²ÎÊý²»ËæÊ±¼ä¶ø¸Ä±äµÄ״̬¡£ÎÞÍâ½ç×÷ÓÃÊÇָϵͳÓëÍâ½çûÓÐÈȺ͹¦µÄ½»»»¡£¶øÏµÍ³µÄƽºâ°üÀ¨Á¦Æ½ºâºÍÈÈÆ½ºâÁ½¸ö·½Ã档ϵͳ´¦ÓÚÁ¦Æ½ºâʱ£¬¸÷²¿·Ö¹¤ÖÊѹÁ¦ÏàµÈ£¬²»·¢ÉúÏà¶ÔÎ»ÒÆ¡£ÏµÍ³´¦ÓÚÈÈÆ½ºâʱ¸÷²¿·Ö¹¤ÖÊÖ®¼äûÓÐÈÈÁ¿´«µÝ£¬Î¶ȾùÔÈÒ»Ö¡£ÓÚÊǹ¤ÖÊÄÚ²¿¾ÍÓÐͳһ¶øÈ·¶¨µÄζȡ¢Ñ¹Á¦ºÍÆäËû״̬²ÎÊý¡£Ö»Óд¦ÓÚÆ½ºâ״̬ʱ״̬²ÎÊý²ÅÄÜÈ·¶¨ÇÒÓÐÒâÒå¡£µ±ÏµÍ³´¦ÓÚ·ÇÆ½ºâ̬ʱ£¬¹¤Öʸ÷²¿·Öζȡ¢Ñ¹Á¦²»µÈ£¬ÎÞ·¨ÓÃͳһµÄ²ÎÊý½øÐÐÃèÊö¡£ 1.3.2»ù±¾×´Ì¬²ÎÊý ÈÈÁ¦Ñ§³£ÓõÄ״̬²ÎÊýÓÐζȡ¢Ñ¹Á¦¡¢±ÈÌå»ý¡¢ìÊ¡¢ìصȡ£¶øÎ¶ȡ¢Ñ¹Á¦ºÍ±ÈÌå»ýÊÇÈý¸ö¿ÉÒÔÖ±½Ó²âÁ¿µÄÎïÀíÁ¿£¬³ÆÎª»ù±¾×´Ì¬²ÎÊý¡£ 1. ÎÂ¶È Î¶ÈÊÇÎïÌåÀäÈȳ̶ȵıêÖ¾¡£°´·Ö×ÓÈÈÔ˶¯Ñ§Ëµ£¬¶ÔÓÚÆøÌ¬¹¤ÖÊ£¬Î¶ÈÊÇÆøÌå´óÁ¿·Ö×ÓÆ½¾ùÒÆ¶¯¶¯ÄܵÄÁ¿¶È¡£ÆøÌå·Ö×ÓÆ½¾ùÒÆ¶¯¶¯ÄÜ´ó£¬Î¶Ⱦ͸ߣ» ·´Ö®ÔòµÍ¡£ µ±Á½¸öζȲ»Í¬µÄÎïÌåÏ໥½Ó´¥£¬ËüÃÇÖ®¼ä½«·¢ÉúÈÈÁ¿´«µÝ£¬¾­¹ýÒ»¶Îʱ¼äºó£¬Á½ÕßζÈÏàµÈ¾Í²»ÔÙÓÐÈÈÁ¿´«µÝ£¬´ïµ½Ò»¸ö¹²Í¬µÄÈÈÆ½ºâ״̬¡£Î¶ȸÅÄîµÄ½¨Á¢ÒÔ¼°Î¶ȵIJⶨ¶¼ÊÇÒÔÈÈÆ½ºâΪÒÀ¾ÝµÄ¡£µ±Î¶ȼÆÓë±»²âÎïÌå´ïµ½ÈÈÆ½ºâʱ£¬Î¶ȼÆÖ¸Ê¾µÄζȾÍÊDZ»²âÎïÌåµÄζȡ£ ºâÁ¿Î¶ȵıê³ß½ÐαꡣÔÚ¹ú¼Êµ¥Î»ÖÆÖУ¬Î¶ȲâÁ¿²ÉÓÃÈÈÁ¦Ñ§Î±꣬ËùÈ·¶¨µÄζȳÆÎªÈÈÁ¦Ñ§Î¶ȣ¬Æä·ûºÅΪT£¬µ¥Î»ÎªK¡£ÈÈÁ¦Ñ§Î±êȡˮµÄÈýÏàµãΪ»ù±¾¶¨µã£¬²¢¶¨ÒåÆäζÈΪ273.16K¡£1KµÈÓÚË®µÄÈýÏàµãÈÈÁ¦Ñ§Î¶ȵÄ1/273.16¡£ ÓëÈÈÁ¦Ñ§Î±겢ÓõϹÓÐÉãÊÏα꣬ËùÈ·¶¨µÄζȳÆÎªÉãÊÏζȣ¬·ûºÅΪt£¬µ¥Î»Îª¡æ¡£ÉãÊÏαêÿ1¡æÓëÈÈÁ¦Ñ§Î±êÿ1KµÄ´óСÏàµÈ£¬µ«Á½Õߵįðʼµã²»Í¬£¬ÉãÊÏαêµÄ0¡æÊÇÔÚÒ»¸öÎïÀí´óÆøÑ¹Ï´¿Ë®µÄ±ùµã£¬ÆäÈÈÁ¦Ñ§Î¶ÈΪ273.15K£¬±ÈË®µÄÈýÏàµãµÄÈÈÁ¦Ñ§Î¶ȵÍ0.01K¡£ ÉãÊÏζÈÓëÈÈÁ¦Ñ§Î¶ÈÖ®¼äµÄ¹ØÏµÎª T=273.15+t(1-1) 2. ѹÁ¦ ´¹Ö±×÷ÓÃÔÚµ¥Î»Ãæ»ýÉϵÄÁ¦³ÆÎªÑ¹Á¦£¬Ó÷ûºÅp±íʾ¡£°´·Ö×ÓÈÈÔ˶¯Ñ§Ëµ£¬ÆøÌåµÄѹÁ¦ÊÇÆøÌåµÄ´óÁ¿·Ö×ÓÏòÈÝÆ÷±ÚÃæ×²»÷Ëù²úÉúµÄƽ¾ù½á¹û¡£ÈôÆøÌå×÷ÓÃÔÚÃæ»ýΪAµÄÈÝÆ÷±ÚÃæÉϵĴ¹Ö±×÷ÓÃÁ¦ÎªF£¬ÄÇô¸Ã±ÚÃæÉϵÄѹÁ¦Îª p=FA(1-2) ÔÚ¹ú¼Êµ¥Î»ÖÆÖУ¬Ñ¹Á¦µÄµ¥Î»ÎªPa£¬1Pa=1N/m2¡£ ¶ø1N=1kg¡¤m/s2£¬kgΪÖÊÁ¿µ¥Î»¡£ ¹¤³ÌÉÏPaµÄµ¥Î»Ì«Ð¡£¬³£²ÉÓÃkPaºÍMPa£¬ËüÃÇÖ®¼äµÄ»»Ëã¹ØÏµÎª 1kPa=103Pa 1MPa=106Pa ¹¤³ÌÖÐÓÐʱҲÓõ½ÆäËûµ¥Î»ÖƵÄѹÁ¦µ¥Î»£¬Èçbar(°Í)¡¢mmH2O¡¢mmHg¡¢atm(±ê×¼´óÆøÑ¹)¡¢at(¹¤³Ì´óÆøÑ¹)µÈ¡£ËüÃÇÖ®¼äµÄ»»Ëã¹ØÏµÎª 1mmH2O=9.81Pa 1mmHg=133.3Pa 1bar=105Pa=0.1MPa 1at=0.981bar=735.6mmHg 1atm=1.01325bar=1.0332at=760mmHg ѹÁ¦Í¨³£Óø÷ÖÖѹÁ¦¼ÆÀ´²â¶¨¡£¶øÑ¹Á¦¼Æ±¾Éí´¦ÓÚ´óÆøÑ¹Á¦pb×÷ÓÃÏ£¬Èçͼ1-2Ëùʾ¡£µ±ÈÝÆ÷ÄÚÆøÌåµÄѹÁ¦´óÓÚ´óÆøÑ¹Á¦pbʱ£¬Ñ¹Á¦¼Æ²âµÃµÄѹÁ¦ÊÇÈÝÆ÷ÄÚµÄѹÁ¦ÓëÍâ½ç´óÆøÑ¹Á¦pbµÄ²îÖµ£¬ÊÇÒ»¸öÏà¶ÔѹÁ¦£¬³ÆÎª±íѹÁ¦£¬Ó÷ûºÅpe±íʾ¡£¶øÈÝÆ÷ÄÚ¹¤ÖʵÄʵ¼ÊѹÁ¦³ÆÎª¾ø¶ÔѹÁ¦£¬Ó÷ûºÅp±íʾ£¬Ôò±íѹÁ¦Ó¦Îª pe=p-pb(1-3) ͼ1-2¸÷ÖÖѹÁ¦¹ØÏµÍ¼ µ±ÈÝÆ÷ÄÚÆøÌåʵ¼ÊѹÁ¦µÍÓÚ´óÆøÑ¹Á¦pbʱ£¬Ñ¹Á¦¼ÆÉϲâµÃµÄѹÁ¦³ÆÎªÕæ¿Õ¶È£¬ÓÃpv±íʾ£¬Ôò pv=pb-p(1-4) ÔÚ¹¤³Ì¼ÆËãÖУ¬Îª¼ò±ãÆð¼û£¬³£°Ñ´óÆøÑ¹Á¦pb½üËÆµØµ±×÷0.1MPaÀ´´¦Àí£¬ÕâÔÚ¼ÆËã½Ï¸ßѹÁ¦Ê±Îó²îºÜС¡£µ«ÔÚ¼ÆËãµÍѹÁ¦Ê±£¬ÌرðÊÇÔÚ¼ÆËãÕæ¿Õ¶Èʱ£¬¾Í»áÒýÆð½Ï´óÎó²î¡£ Àý1-1ÒÑÖªÁ½ÏµÍ³ÄÚ±íѹÁ¦·Ö±ðΪ0.015MPaºÍ1.5MPa£¬µ±Ê±ÆøÑ¹¼ÆµÄ¶ÁÊýΪ101325Pa£¬ÊÔ¼ÆËãÁ½ÏµÍ³µÄ¾ø¶ÔѹÁ¦¡£ ½âÒÑÖªÁ½ÏµÍ³µÄ±íѹÁ¦·Ö±ðΪ pe1=0.015MPa£¬pe2=1.5MPa ÆøÑ¹¼Æ¶ÁÊýΪ pb=0.1013MPa ËùÒÔÁ½ÏµÍ³µÄ¾ø¶ÔѹÁ¦·Ö±ðΪ p1=pe1+pb=0.1163(MPa) p2=pe2+pb=1.6013(MPa) 3. ±ÈÌå»ýÓëÃÜ¶È ±ÈÌå»ýÖ¸µ¥Î»ÖÊÁ¿µÄ¹¤ÖÊËùÕ¼ÓеÄÌå»ý£¬Ó÷ûºÅv±íʾ£¬µ¥Î»Îªm3/kg¡£ÈôÖÊÁ¿ÎªmµÄÆøÌ壬ռÓеÄÌå»ýΪV£¬Ôò±ÈÌå»ýΪ v=Vm(1-5) µ¥Î»Ìå»ýÎïÖʵÄÖÊÁ¿³ÆÎªÃܶȣ¬Ó÷ûºÅ¦Ñ±íʾ£¬µ¥Î»Îªkg/m3¡£ÈôÌå»ýΪVµÄÆøÌ壬¾ßÓеÄÖÊÁ¿Îªm£¬ÔòÃܶÈΪ ¦Ñ=mV(1-6) ÏÔÈ»£¬±ÈÌå»ýºÍÃܶȻ¥Îªµ¹Êý£¬¼´ ¦Ñv=1(1-7) 1.4ÀíÏëÆøÌå״̬·½³Ì ϵͳµÄƽºâ״̬ÓÃ״̬²ÎÊýÀ´ÃèÊö£¬±íʾ»ù±¾×´Ì¬²ÎÁ¿Ö®¼äº¯Êý¹ØÏµµÄ·½³Ì³ÆÎª×´Ì¬·½³Ì¡£ Ä³Ð©ÆøÌåÔÚÖÊÁ¿Îª¶¨ÖµµÄÇé¿öÏ£¬Èý¸ö»ù±¾×´Ì¬²ÎÁ¿Ö®¼äµÄ¹ØÏµ¿ÉÓÉÎïÀíѧµÄ²£Òâ¶ú-ÂíÀï°ÂÌØ¶¨ÂÉ¡¢¸Ç¡¤ÂÀÈø¿Ë¶¨ÂɺͲéÀí¶¨ÂÉ˵Ã÷¡£×ÛºÏÕâЩ¶¨ÂÉ¿ÉÒԵõ½ÈçϹØÏµÊ½£º pv=RgT(1-8) ʽÖУ¬p ¡ª¡ªÆøÌåµÄ¾ø¶ÔѹÁ¦,Pa£» T¡ª¡ªÆøÌåµÄÈÈÁ¦Ñ§Î¶È,K£» v¡ª¡ªÆøÌåµÄ±ÈÌå»ý,m3/kg£» Rg¡ª¡ªÆøÌå³£Êý£¬ÓëÆøÌåµÄÐÔÖÊÓйأ¬¶øÓëÆøÌåµÄ״̬Î޹ء£¶ÔÓÚͬһÖÖÆøÌå,RgΪһ¸ö³£Êý,²»Í¬ÆøÌåµÄÆøÌå³£ÊýÖµ²»Í¬¡£Æäµ¥Î»ÎªJ/(kg¡¤K)¡£ ÉÏʽ½öÊÊÓÃÓÚ1kgÖÊÁ¿µÄÆøÌ塣״̬²ÎÁ¿Âú×ãÉÏʽµÄÆøÌå³ÆÎªÀíÏëÆøÌ壬ʽ(1-8)³ÆÎªÀíÏëÆøÌå״̬·½³Ìʽ¡£ ËùνÀíÏëÆøÌåÊÇÒ»ÖÖ³éÏóµÄ¼ÙÏëÆøÌ壬ÕâÖÖÆøÌ屨Ðë·ûºÏÁ½Ìõ¼Ù¶¨£º ¢ÙÆøÌåµÄ·Ö×ÓÊÇһЩµ¯ÐԵġ¢²»Õ¼ÓÐÌå»ýµÄÖʵ㣻 ¢Ú·Ö×ÓÖ®¼äûÓÐÏ໥×÷ÓÃÁ¦¡£²»·ûºÏÕâÁ½¸ö¼ÙÉèÌõ¼þµÄÆøÌåÔò³ÆÎªÊµ¼ÊÆøÌå¡£ ÈÈÁ¦Ñ§ÒýÈëÀíÏëÆøÌåµÄ¸ÅÄÊÇΪÁ˱ãÓÚ·ÖÎö¼ÆËã¡£ÔÚÕâЩÌõ¼þÏ£¬ÆøÌå·Ö×ÓÔ˶¯¹æÂɿɴó´ó¼ò»¯£¬×´Ì¬²ÎÊýÖ®¼äÖ»´æÔÚ¼òµ¥µÄº¯Êý¹ØÏµ¡£ËäÈ»ÀíÏëÆøÌåÊÇÒ»ÖÖ³éÏóµÄ¼ÙÏëÆøÌ壬µ«È´ÓнϴóµÄʵÓÃÒâÒ塣ʵÑéÖ¤Ã÷£¬µ±Ñ¹Á¦½ÏµÍ»òζȽϸßʱ£¬ÆøÌåµÄ±ÈÌå»ý½Ï´ó£¬·Ö×Ó¼äµÄ×÷ÓÃÁ¦¼°·Ö×Ó±¾ÉíµÄÌå»ý¿ÉÒÔºöÂÔ£¬´ËʱÕâÐ©ÆøÌå¿ÉÒÔ¿´×÷ÀíÏëÆøÌå¡£ÔÚͨ³£Ñ¹Á¦ºÍζÈÏ£¬¹¤³ÌÖг£ÓÃµÄÆøÌåO2¡¢N2¡¢H2¡¢CO¡¢CO2µÈÒÔ¼°ÓÉÕâÐ©ÆøÌå×é³ÉµÄ¿ÕÆø¡¢ÑÌÆø£¬ÓÉÓÚÔ¶ÀëҺ̬£¬ÔÚ¹¤³Ì¼ÆËãËùÒªÇóµÄ¾«¶È·¶Î§ÄÚ£¬¿É×÷ΪÀíÏëÆøÌåÀ´´¦Àí¡£µ±Ñ¹Á¦½Ï¸ß»òζȽϵͻò½Ó½üÓÚҺ̬ʱ£¬ÆøÌåµÄ±ÈÌå»ýС£¬·Ö×ÓÖ®¼äµÄ¾àÀë½Ï½ü£¬Òò´Ë·Ö×Ó±¾ÉíµÄÌå»ýÒÔ¼°·Ö×ÓÖ®¼äµÄÏ໥×÷ÓÃÁ¦²»ÄܺöÊÓ£¬ÈçÕôÆû¶¯Á¦×°ÖÃÖеÄË®ÕôÆøÒÔ¼°Ñ¹ËõÖÆÀä×°ÖÃÖеÄÖÆÀä¼ÁÕôÆøµÈ£¬¾Í²»Äܵ±×÷ÀíÏëÆøÌå¿´´ý£¬³ÆÆäΪʵ¼ÊÆøÌå»òÕôÆø¡£ ¶ÔÖÊÁ¿ÎªmµÄÀíÏëÆøÌ壬״̬·½³ÌµÄÐÎʽΪ pV=mRgT(1-9) ʽÖÐV±íʾÖÊÁ¿ÎªmµÄÆøÌåÌå»ý¡£ ÓÉÓÚmRg²»±ä,ʽ£¨1-9£©ÓֿɱíʾΪ pVT=ºãÁ¿(1-10) Òâ¼´£¬ÀíÏëÆøÌå´¦ÔÚÈÎһƽºâ̬ʱ£¬ÆäѹÁ¦ÓëÈÝ»ýµÄ³Ë»ýÓëζȵıÈÖµµÈÓÚͬһ³£Êý¡£ ÔÚ±ê×¼×´¿öÏ£¬Ê½(1-10)¾Í±äΪ p0V0T0=ºãÁ¿(1-11) ʽÖÐ p0=1.01325¡Á105Pa T0=273.15K(¼´0¡æ) ¹ú¼Êµ¥Î»ÖÆÖУ¬ÎïÖʵÄÁ¿ÒÔĦ¶û(mol)Ϊµ¥Î»£¬1molÎïÖʵÄÖÊÁ¿³ÆÎªÄ¦¶ûÖÊÁ¿£¬¼ÇΪM£¬µ¥Î»Îªkg/mol¡£1kmolÆøÌåµÄÖÊÁ¿ÔÚÊýÖµÉϵÈÓÚÆøÌåµÄÏà¶Ô·Ö×ÓÖÊÁ¿¡£ÀýÈ磬Ñõ¡¢µªºÍ¿ÕÆøµÄĦ¶ûÖÊÁ¿·Ö±ðΪ32.00kg/kmol¡¢28.02kg/kmolºÍ28.96kg/kmol¡£1molÎïÖʵÄÌå»ý³ÆÎªÄ¦¶ûÌå»ý£¬¼ÇΪVm,Vm=Mv¡£ µ±²ÉÓÃĦ¶ûÖÊÁ¿ºÍĦ¶ûÌå»ýʱ£¬ÀíÏëÆøÌåµÄ״̬·½³Ìʽ±ä»»Îª pVm=MRgT ÈôÁîR=MRg,Ôò pVm=RT(1-12) R³ÆÎªÄ¦¶ûÆøÌå³£Êý¡£ °¢·üÙ¤µÂÂÞ¼Ù˵ָ³ö£¬ÏàͬζȺÍѹÁ¦ÏÂÈÎºÎÆøÌåµÄĦ¶ûÌå»ýÏàµÈ¡£¸ù¾ÝÕâ¸ö¼Ù˵£¬ÓÉʽ(1-11)¿ÉÒÔ¿´³ö£º R¶ÔÓÚ¸÷ÖÖÆøÌåÓÐÏàͬµÄÊýÖµ¡£Òò´Ë£¬RÓÖ³ÆÎªÍ¨ÓÃÆøÌå³£Êý£¬ÆäֵΪ R=8.314J/(mol¡¤K) ¶ÔÓÚ²»Í¬ÖÖÀàµÄÆøÌ壬1kgÆøÌåµÄÆøÌå³£ÊýRgÓв»Í¬µÄÖµ¡£ËüÓëͨÓÃÆøÌå³£ÊýRµÄ¹ØÏµÎª Rg=RM(1-13) ÀûÓÃĦ¶ûÆøÌå³£Êý£¬ÖÊÁ¿ÎªmµÄÀíÏëÆøÌå״̬·½³Ìʽ(1-9)ÓÖ¿ÉÒÔд³É pV=nRT(1-14) ʽÖÐn=mM£¬³ÆÎªÎïÖʵÄÁ¿¡£ Àý1-2ÓÐÒ»³äÆø¸ÕÐÔÈÝÆ÷£¬Ìå»ýΪ5m3£¬ÈÝÆ÷ÄÚÆøÌåµÄ±íѹÁ¦Îªpe=0.85MPa£¬Î¶ȼƶÁÊýΪt=40¡æ£¬ÎÊÔÚ±ê׼״̬ÏÂÆøÌåÌå»ý¿É´ï¶àÉÙ£¿ ½âÉè´óÆøÑ¹Á¦Îª pb=0.1MPa ÈÝÆ÷ÄÚÆøÌå¾ø¶ÔѹÁ¦ p=pe+pb=0.95(MPa) ÈÈÁ¦Ñ§ÎÂ¶È T=273+t=313(K) ÓÉÓÚÈÝÆ÷ÄÚÆøÌåÖÊÁ¿±£³ÖÎȶ¨£¬ËùÒÔÓÐ pVT=p0V0T0 ¼´ V0=VpT0p0T=5¡Á0.95¡Á2730.1¡Á313=41.43(m3) Àý1-3ÑõÆøÆ¿µÄÌå»ýΪ0.05m3£¬Æ¿ÄÚÑõÆøµÄѹÁ¦Îª8MPa£¬ÊÒÎÂΪ27¡æ¡£ºóÀ´ÓÃÈ¥Ò»²¿·ÖÑõÆø£¬Ñ¹Á¦½µµÍΪ6MPa¡£ÎÊÓÃÈ¥Á˶àÉÙǧ¿ËµÄÑõÆø£¿ ½âÔÚÒÑÖªÌõ¼þÏ£¬ÑõÆø¿É×÷ΪÀíÏëÆøÌåÀ´¿´´ý£¬ÑõÆøµÄĦ¶ûÖÊÁ¿M=32¡Á10-3kg/mol£¬¹Ê Rg=RM=8.31432¡Á10-3=259.81(J/(kg¡¤K)) (1) ʹÓÃǰƿÄÚÔ­ÓеÄÑõÆøÖÊÁ¿Îª m1=p1V1RgT1 (2) ʹÓúóÆ¿ÄÚÔ­ÓеÄÑõÆøÖÊÁ¿Îª m2=p2V2RgT2 (3) ÓÃÈ¥µÄÑõÆøÖÊÁ¿Îª ¦¤m=m1-m2=(p1-p2)VRgT=(8-6)¡Á106¡Á0.05259.81¡Á300 =1.2829(kg) 1.5׼ƽºâ¹ý³ÌÓë¿ÉÄæ¹ý³Ì 1.5.1p-ÿðþ½›ͼ ¹¤ÖʵÄÈý¸ö»ù±¾×´Ì¬²ÎÊýp¡¢v¡¢TÖ®ÖÐÖ»ÒªÒÑÖªÈÎÒâÁ½¸ö£¬ÁíÒ»¸öÒ²¾ÍËæÖ®È·¶¨ÁË¡£±ÈÈçζȿÉÓÉѹÁ¦ºÍ±ÈÌå»ýÈ·¶¨£¬Æäº¯Êý¹ØÏµÎª T=f(p,v) Òò´Ë£¬Á½¸ö¶ÀÁ¢µÄ״̬²ÎÊý¾Í¿ÉÒÔÈ·¶¨¹¤ÖÊ״̬¡£ÓÚÊÇ£¬¿ÉÒÔÓÃÁ½¸ö¶ÀÁ¢µÄ²ÎÊýÎª×ø±ê£¬¹¹³ÉÆ½Ãæ×ø±êͼ£¬Í¼ÖеÄÿһ¸öµã±íʾһ¸öƽºâ״̬¡£¾­³£Ê¹ÓõÄÊÇ·Ö±ðÒÔpºÍvΪ×Ý¡¢ºá×ø±êµÄÆ½ÃæÍ¼£¬³ÆÎªp-vͼ¡£Í¼ÖÐÿһµã¶ÔÓ¦µÄpºÍvֵ֮ȷ¶¨Ò»¸öƽºâ̬¡£·Çƽºâ̬ûÓÐÈ·¶¨µÄ״̬²ÎÊý£¬ÎÞ·¨ÔÚp-vͼÉϱíʾ³öÀ´¡£ 1.5.2ÈÈÁ¦¹ý³Ì ´¦ÓÚÆ½ºâ̬µÄϵͳÎÞÍâ½çÓ°ÏìʱÆä״̬²ÎÊý²»±ä¡£Ò»µ©ÏµÍ³ÓëÍâ½ç·¢ÉúÁËÏ໥×÷Óã¬Æ½ºâ±»´òÆÆ£¬×´Ì¬¾Í»á·¢Éú±ä»¯£¬²¢ÏòеÄ״̬¹ý¶É¡£Õâʱ£¬ÏµÍ³½«¾­ÀúÒ»¸öÈÈÁ¦¹ý³Ì¡£ ϵͳ´ÓÒ»¸ö״̬µ½ÁíÒ»¸ö״̬Ëù¾­ÀúµÄ±ä»¯¹ý³Ì³ÆÎªÈÈÁ¦¹ý³Ì£¬¼ò³Æ¹ý³Ì£¬ÊÇÓÉϵͳËù¾­ÀúµÄÎÞÊý¸öÖмä״̬Ëù×é³ÉµÄ¡£ 1. ׼ƽºâ¹ý³Ì ÔÚ¹ý³Ì½øÐеÄÿһʱ¿Ìϵͳ״̬¶¼ÎÞÏÞ½Ó½üƽºâ̬£¬Ôò¸Ã¹ý³Ì³ÆÎª×¼Æ½ºâ¹ý³Ì¡£ Èçͼ1-3Ëùʾ£¬Æû¸×Öй¤ÖÊ´¦ÓÚÆ½ºâ̬1£¬ÆäѹÁ¦p1ºÍÍâ½çѹÁ¦p01ÏàµÈ¡£ÈôÍâ½çѹÁ¦½µµ½p02£¬¹¤Öʽ«Íƶ¯»îÈûÏòÓÒÒÆ¶¯¡£¶øÏµÍ³ÄÚ²¿Ñ¹Á¦³öÏÖ²»¾ùÔÈ״̬£¬¸÷²¿·Ö¹¤ÖÊÖ®¼äÁ¢¼´¿ªÊ¼Î»ÒÆ£¬Á¦Í¼»Ö¸´Æ½ºâ£¬ ͼ1-3׼ƽºâ¹ý³Ì Ö±µ½¹¤ÖÊѹÁ¦p2µÈÓÚp02£¬´ïµ½ÐÂµÄÆ½ºâ̬¡£ÍⲿѹÁ¦ÔٴμõС£¬ÉÏÊö¹ý³Ì½«Öظ´½øÐУ¬Ö±µ½×´Ì¬µã3¡£×´Ì¬1¡¢2¡¢3¾ùΪƽºâ̬£¬µ«1¡ª2£¬2¡ª3Ö®¼äµÄ״̬ÊDz»Æ½ºâµÄ¡£µ«ÈôÍâ½çѹÁ¦Ã¿´ÎÖ»¼õÉÙÒ»¸ö΢СÁ¿£¬ÇÒÁ½´ÎѹÁ¦±ä»¯Ö®¼äµÄʱ¼äÓֱȽϳ¤£¬ÔÚÍâ½çѹÁ¦µÚ¶þ´Î±ä»¯Ö®Ç°ÏµÍ³Òѻָ´Æ½ºâ£¬Ôò¹ý³ÌÖÐϵͳʼÖÕÆ«ÀëÆ½ºâ̬²»Ô¶¡£ÕâÑùµÄ¹ý³Ì¾ÍÊÇ׼ƽºâ¹ý³Ì¡£ ¶ÔÓÚÈȲ»Æ½ºâÒý·¢µÄÈÈÁ¦¹ý³Ì£¬ÈôβîºÜС£¬ÇÒ¹ý³Ì½øÐзdz£»ºÂý£¬Ò²Í¬ÑùÊÇ׼ƽºâ¹ý³Ì¡£ ׼ƽºâ¹ý³ÌÔÚp-vͼÉϿɱíÏÖΪһÌõʵÏß¡£ 2. ¿ÉÄæ¹ý³ÌºÍ²»¿ÉÄæ¹ý³Ì ϵͳ´Ó³õʼ״̬³ö·¢£¬¾­ÀúijһÈÈÁ¦¹ý³ÌÖ®ºóµ½´ïÖÕ̬¡£Èç¹ûϵͳÄܹ»ÑØ×Ÿùý³ÌµÄ·¾¶ÄæÐлص½³õʼ״̬£¬¶øÏµÍ³ÓëÍâ½ç¾ùδ³öÏÖÈκα仯£¬Ôò´Ë¹ý³Ì³ÆÎª¿ÉÄæ¹ý³Ì¡£·´Ö®£¬ÈôϵͳºÍÍâ½ç²»ÄÜÍêÈ«¸´Ô­£¬Ôò³ÆÎª²»¿ÉÄæ¹ý³Ì¡£ÊµÏÖ¿ÉÄæ¹ý³Ì±ØÐë¾ß±¸Á½¸öÌõ¼þ£º (1) ϵͳ¾­ÀúµÄ¹ý³ÌÊÇ׼ƽºâ¹ý³Ì£» (2) ϵͳÓëÍâ½ç²»´æÔÚĦ²ÁºÍβÈȵȺÄɢЧӦ¡£ ºÄɢЧӦÔì³ÉÄÜÁ¿Ëðʧ£¬Êǹý³ÌÎÞ·¨ÊµÏÖ¿ÉÄæµÄÔ­Òò£¬ÓÖ³ÆÎª²»¿ÉÄæÒòËØ¡£Êµ¼Ê¹ý³Ì¶¼»á´æÔÚһЩ²»¿ÉÄæÒòËØ¡£ÔÚÈÈÁ¦Ñ§µÄÑо¿ÖÐÐí¶àʵ¼Ê¹ý³Ì¿ÉÒÔ¼ò»¯Îª¿ÉÄæ¹ý³Ì£¬ÔÙ×÷Êʵ±ÐÞÕý¡£ 3. ÈÈÁ¦Ñ­»· ͼ1-4ÈÈÁ¦Ñ­»· ¹¤ÖÊ´Ó³õʼ״̬³ö·¢¾­ÀúijЩ¹ý³ÌÖ®ºóÓֻص½³õ̬£¬ÔÚp-vͼÉÏÐγÉÒ»Ìõ±ÕºÏµÄÇúÏߣ¬Èçͼ1-4Ëùʾ¡£ÕâÖÖ·â±ÕµÄ¹ý³Ì³ÆÎªÈÈÁ¦Ñ­»·£¬¼ò³ÆÑ­»·¡£ È«²¿ÓÉ¿ÉÄæ¹ý³Ì×é³ÉµÄÑ­»·³ÆÎª¿ÉÄæÑ­»·£» º¬Óв»¿ÉÄæ¹ý³ÌµÄÑ­»·³ÆÎª²»¿ÉÄæÑ­»·¡£Ö»ÓÐʵÏÖÑ­»·²ÅÄÜʹÈÈ»úʵÏÖÁ¬ÐøµØ×ö¹¦¡£ 1.6¹¦Á¿ºÍÈÈÁ¿ ϵͳÓëÍâ½çµÄÄÜÁ¿½»»»ÐÎʽÓÐÁ½ÖÖ£º ×ö¹¦ºÍÈÈ´«µÝ¡£ 1.6.1¹¦Á¿ ϵͳÓëÍâ½ç´æÔÚѹÁ¦²îʱ·¢ÉúµÄÄÜÁ¿´«µÝÐÎʽÊÇ×ö¹¦¡£¹¦µÄµ¥Î»Îª½¹¶ú£¬¼ÇΪJ£¬1J=1N¡¤m¡£µ¥Î»ÖÊÁ¿µÄ¹¤ÖÊËù×öµÄ¹¦³ÆÎª±È¹¦£¬µ¥Î»ÎªJ/kg¡£ ¹¤ÖÊÌå»ýÅòÕÍʱ¶ÔÍâËù×öµÄ¹¦³ÆÎªÅòÕ͹¦£» Íâ½çѹËõ¹¤ÖÊʱ¶ÔϵͳËù×öµÄ¹¦³ÆÎªÑ¹Ëõ¹¦¡£Á½Õßͳ³ÆÎªÈÝ»ý±ä»¯¹¦¡£ ͼ1-5¹¤ÖʵÄÅòÕ͹¦ Èçͼ1-5Ëùʾ£¬ÉèÓÐÖÊÁ¿ÎªmµÄÆøÌ幤ÖÊÔÚÆû¸×ÖпÉÄæÅòÕÍ£¬»îÈûÒÆ¶¯Ò»Î¢Ð¡¾àÀëdxʱ£¬¹¤ÖÊ×ö¹¦Îª ¦ÄW=Fdx=pAdx=pdV(1-15) ÆäÖУ¬AΪ»îÈûÃæ»ý£¬dVΪ¹¤ÖÊÈÝ»ý±ä»¯Á¿¡£µ±¹¤ÖÊ´Ó״̬1ÅòÕ͵½×´Ì¬2ʱËù×öµÄÅòÕ͹¦Îª W=¡Ò21pdV(1-16) µ¥Î»ÖÊÁ¿µÄ¹¤ÖÊËù×öµÄ±ÈÅòÕ͹¦¼ÇΪw£º ¦Äw=1mpdV(1-17) w=1m¡Ò21pdV=¡Ò21pdVm=¡Ò21pdv(1-18) ¹¤Öʱ»Ñ¹ËõʱdVºÍdvΪ¸º£¬¹¦Á¿Ò²Îª¸º¡£Òò´Ë£¬¹¤ÖÊÅòÕͶÔÍâ×ö¹¦ÎªÕý£¬Íâ½çѹËõ¹¤ÖʶÔϵͳ×ö¹¦Îª¸º¡£ ÔÚ p-vͼÉϹý³ÌÇúÏßÓëºá×ø±êÖ®¼äÇú±ßÌÝÐεÄÃæ»ý±íʾ¹ý³ÌÖÐϵͳÓëÍâ½ç½»»»µÄ±È¹¦£¬Èçͼ1-5Ëùʾ¡£Òò´Ë£¬p-vͼÓÖ³ÆÎªÊ¾¹¦Í¼¡£ ϵͳֻÓо­Àú¹ý³Ìʱ²Å»áÓëÍâ½çÓй¦µÄ½»»»¡£ÔÚ³õ¡¢ÖÕ̬ÏàͬʱÈôϵͳ¾­ÀúµÄ¹ý³Ì²»Í¬£¬ÔòÓëÍâ½ç½»»»µÄ¹¦Á¿Ò²²»µÈ¡£ÔÚp-vͼÉϱíÏÖΪ²»Í¬µÄ¹ý³ÌÇúÏß¼°Çú±ßÌÝÐÎÃæ»ý¡£Òò´Ë£¬¹¦Êǹý³ÌÁ¿¶ø·Ç״̬²ÎÊý¡£